The total number of radial nodes for a given orbital is _____

n - 1

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n - l - 1

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n + l + 1

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n + 1

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Solution

The correct option is B
n - l - 1

Total nodes for orbital of n is n - 1

Total angular nodes is l

Thus, total radial nodes is n - 1 - l

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Similar questions

L = lim n \to \infty \frac{1}{n^{4}} [1 (n \sum k = 1 k) + 2 (n - 1 \sum k = 1 k) + 3 (n - 2 \sum k = 1 k) + . . . . . . + n .1]

The number of terms in the expansion of (a + b + c)ⁿ are:

L = lim n \to \infty n \frac{1}{4} [1. (n \sum k = 1 k) + 2. (n - 1 \sum k = 1 k) + 3. (n - 2 \sum k = 1 k) + . . . + n .1]

n = 4

l = 1

f (n) = {cot}^{- 1} (n + 3) - 2 {cot}^{- 1} (n + 1) + {cot}^{- 1} (n - 1)

n \in N,

\infty \sum n = 1 f (n)

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