The total number of shared electrons in the lewis dot structure of a $O_{2}$ molecule is:
4

Open in App

Solution

The correct option is A 4
The electronic configuration of an oxygen atom is 2,6; hence, it has 6 valence electrons.
It combines with another oxygen atom to form an oxygen $(O_{2})$ molecule.
During this, '2 electron pairs', i.e., '4 electrons' are shared between the two atoms.
In the given diagram, the shared pairs of electrons are represented as crosses and the rest of valence electrons as dots in the lewis dot structure.

Suggest Corrections

Similar questions

O_{2}

O_{2}

The number of electrons in a Lewis dot structure of each bonded atom should always sum up to:

Join BYJU'S Learning Program