The total number of stereoisomers of $(C H_{3} - C H = C H - C H_{2})_{3} C H$ is:

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Solution

The correct option is B 4
The compound $(C H_{3} - C H = C H - C H_{2} -)_{3} C H$ has four geometrical isomers. Which are either of E type or Z type geometrical isomerism.

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C H_{3} - C H = C H - C | B r H - C H_{3}

P h - O | | S - C H = C H - C H_{2} - C H = C = C = C H - C H = C H - C H_{3}

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H = C = C H - C H = C H - C H = C = C H - C H_{3}

C H_{3} - C | C H_{3} H - C H_{2} - C H_{3} C l_{2} - - \to h v

(x)

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