The total number of unpaired electrons present in the complex $K_{3} [C r (o x a l a t e)_{3}]$ is

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Solution

Answer: (3)
oxalate is a bidentate ligand.
In given complex $K_{3} [C r (o x)_{3}]$ , chromium is in + 3 oxidation state.
Outer electronic configuration of Cr is
$C r \to 3 d^{5} 4 s^{1}$

$C r^{3 +} \to 3 d^{3}$

Thus, 3 it has unpaired electrons.
The hybridization of chromium in the complex is $d^{2} s p^{3}$

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