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Formation of Ions in Metals

the total num...

Question

the total number of valence electrons in 4.2 n₃^- ion is

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Solution

Your question is the total number of valence electrons in 4.2 g of N ³^- ion?
$N u m b e r o f m o l e s = \frac{G i v e n m a s s i n g}{M o l a r m a s s} = \frac{4.2}{14} = 0.3 m o l e N u m b e r o f N^{3 -} i o n = M o l e \times a v o g a d r o n u m b e r = 0.3 \times 6.022 \times 10^{23} = 1.8066 \times 10^{23} i o n s N^{3 -} h a s 5 + 3 v a l e n c e e l e c t r o n S o 1.8066 \times 10^{23} i o n s h a v e = 8 \times 1.8066 \times 10^{23} = 14.45 \times 10^{23} v a l e n c e e l e c t r o n$

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Formation of Ions in Metals

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