The total pressure of a mixture of 6.4 grams of oxygen and 5.6 grams of nitrogen present in a 2 lit vessel is 1200mm. What is the partial pressure of nitrogen in mm?

1200

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600

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900

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200

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Solution

The correct option is B
600

$N_{2} = \frac{5.6}{28} \Rightarrow 0.2$

$O_{2} = \frac{6.4}{32} \Rightarrow 0.2$

$P_{N_{2}} = \frac{0.2}{0.4} \times P$

$\Rightarrow \frac{1}{2} \times 1200 \Rightarrow 600 m m$

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The total pressure of a mixture of 6.4 grams of oxygen and 5.6 grams of nitrogen present in a 2 lit vessel is 1200mm. What is the partial pressure of nitrogen in mm?

The correct option is B 600 N2=5.628⇒0.2 O2=6.432⇒0.2 PN2=0.20.4×P ⇒12×1200⇒600 mm

The correct option is B
600

$N_{2} = \frac{5.6}{28} \Rightarrow 0.2$

$O_{2} = \frac{6.4}{32} \Rightarrow 0.2$

$P_{N_{2}} = \frac{0.2}{0.4} \times P$

$\Rightarrow \frac{1}{2} \times 1200 \Rightarrow 600 m m$