The total revenue in rupees received from the sale of x units of a product is given by $R (x) = 3 x^{2} + 36 x + 5$ . The marginal revenue, when x=15 is

a) 116

b) 96

c) 90

d) 126

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Solution

Given, $R (x) = 3 x^{2} + 36 x + 5$
\therefore Marginal Revenue $[M R] = \frac{d R}{d x} = \frac{d}{d x} (3 x^{2} + 36 x + 5) = 6 x + 36$
When x=15, $M R = 6 \times 15 + 36 = 126$
Hence, the required marginal revenue is Rs. 126.
Hence, the correct option is (d).

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The total revenue received from the sale of x units of a product is given by $R (x) = 3 x^{2} + 36 x + 5$ .The marginal revenue, when x = 15

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