The total revenue in Rupees received from the sale of $x$ units of a product is given by $R (x) = 3 x^{2} + 36 x + 5$ . The marginal revenue, when $x = 15$ is.

116

No worries! We‘ve got your back. Try BYJU‘S free classes today!

126

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C 126
We have, $R (x) = 3 x^{2} + 36 x + 5$
$\Rightarrow Marginal revenue = \frac{d R (x)}{d x} = 6 x + 36$
Thus at $x = 15, Marginal revenue = 6 (15) + 36 = 126$

Suggest Corrections

Similar questions

Q. The total revenue in Rupees received from the sale of

x

units of a product is given by

R (x) = 3 x^{2} + 36 x + 5

. The marginal revenue, when

x = 15

The total revenue in rupees received from the sale of x units of a product is given by $R (x) = 3 x^{2} + 36 x + 5$ . The marginal revenue, when x=15 is

a) 116

b) 96

c) 90

d) 126

The total revenue in Rupees received from the sale of x units of a product is given by

. The marginal revenue, when is

(A) 116 (B) 96 (C) 90 (D) 126

The total revenue received from the sale of x units of a product is given by $R (x) = 3 x^{2} + 36 x + 5$ .The marginal revenue, when x = 15

Q. The total revenue in Rupees received from the sale of

x

units of a product is given by

R (x) = 13 x^{2} + 26 x + 15

.
Find the marginal revenue when

x = 7

Join BYJU'S Learning Program

The total revenue in Rupees received from the sale of x units of a product is given by R(x)=3x2+36x+5. The marginal revenue, when x=15 is.

The correct option is C 126We have, R(x)=3x2+36x+5⇒Marginal revenue=dR(x)dx=6x+36Thus at x=15,Marginal revenue=6(15)+36=126

The total revenue in Rupees received from the sale of $x$ units of a product is given by $R (x) = 3 x^{2} + 36 x + 5$ . The marginal revenue, when $x = 15$ is.

The correct option is C 126
We have, $R (x) = 3 x^{2} + 36 x + 5$
$\Rightarrow Marginal revenue = \frac{d R (x)}{d x} = 6 x + 36$
Thus at $x = 15, Marginal revenue = 6 (15) + 36 = 126$