The total surface area of a hollow metal cylinder- open at both ends of external radius 8 cm and height 10 cm is 338 p cm 2- Taking r to be inner radius- obtain an equation in r and use it to obtain the thickness of the metal in the cylinder-

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Standard IX

Mathematics

Volume of a right circular cylinder

The total sur...

Question

The total surface area of a hollow metal cylinder, open at both ends of external radius 8 cm and height 10 cm is 338 p cm². Taking r to be inner radius, obtain an equation in r and use it to obtain the thickness of the metal in the cylinder.

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Solution

Data given in the problem is as follows:

Given cylinder is a hollow cylinder

External radius (R) = 8cm

Height (h) = 10cm

Total Surface Area = 338π

We have to obtain an equation in r, where r is the inner radius of the cylinder and using this equation we have to find the thickness of the cylinder.

We know that,

Total Surface Area of a hollow cylinder =

Therefore,

=

= 338

Thickness = R – r = 8 – 5 = 3 cm

Thickness of the cylinder is 3 cm

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The total surface area of a hollow metal cylinder, open at both ends of external radius 8 cm and height 10 cm is 338 p cm2. Taking r to be inner radius, obtain an equation in r and use it to obtain the thickness of the metal in the cylinder.

The total surface area of a hollow metal cylinder, open at both ends of external radius 8 cm and height 10 cm is 338 p cm². Taking r to be inner radius, obtain an equation in r and use it to obtain the thickness of the metal in the cylinder.