The total surface area of a rectangular box of dimensions a, 2a and 3a is ___.
A
22a2
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B
20a2
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C
12a2
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D
23a2
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Solution
The correct option is A22a2
Given, sides are a, 2a, 3a The total surface area of a cuboid of dimensions l,b and h = 2(lb+bh+lh) T.S.A=2((a×2a)+(2a×3a)+(3a×a)) = 2(2a2+6a2+3a2) = 22a2