The total surface area of a rectangular box of dimensions a, 2a and 3a is
20a2
12a2
22a2
24a2
The total surface area of a cuboid.of dimensions l,b and h is
Total surface area=2(lb+bh+lh)
So, in this case, T.S.A.=2(2a2+6a2+3a2)=22a2
The total surface area of a box which is in the form of a cuboid whose dimensions are l×b×h is _______.
The total surface area of a box which is in the form of a cuboid whose dimensions are l×b×h is__________.
Question 2 A rectangular piece of dimensions 3 cm x 2 cm was cut from a rectangular sheet of paper of dimensions 6 cm x 5 cm (see the figure). Area of remaining sheet of paper is (a) 30 cm2 (b) 36 cm2 (c) 24 cm2 (d) 22 cm2