The total two-digit numbers which are divisible by $5$ , are

17

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18

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19

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20

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Solution

The correct option is B $18$
$10, 15, 20, . . . . . . . . 95$
$n$ th term of AP $= a + (n - 1) d$
$\Rightarrow 95 = 10 + (n - 1) 5$
$\Rightarrow 95 = 10 + 5 n - 5$
$\Rightarrow 95 = 5 n + 5$
$\Rightarrow n = 18$
Hence, required numbers $= 18$

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