2
You visited us
2
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Heat of Reaction
The total vap...
Question
The total vapour pressure of a mixture of 1 mole of A(partial pressure = 200) and 3 mole of B(partial pressure = 360) is 350 mm Hg. Then this is positive deviation or negative deviation
Open in App
Solution
Suggest Corrections
15
Similar questions
Q.
1 mole of Benzene
(
P
∘
B
e
n
z
e
n
e
=
42
mm Hg
)
and 2 mole of toluene
(
P
∘
t
o
l
u
e
n
e
=
36
mm Hg
)
will have
Q.
A cylinder contains 0.3 mole
N
2
, 0.1 mole
O
2
and 0.1 mole
H
e
. If the total pressure of gas mixture is 1 atmosphere, the partial pressure of
O
2
in
m
m
of
H
g
is:
Q.
The total vapour pressure of a mixture of 1 mol A
(
P
0
A
=
130
t
o
r
r
)
and 2 mol B
(
P
0
B
=
240
t
o
r
r
)
is 200 mm. In this case:
Q.
Total vapour pressure of mixture of
1
mole of
A
(
P
0
A
=
150
m
m
)
and 2 mole of B
(
P
0
B
=
240
m
m
)
is
200
mm. In this case :
Q.
Vapour pressure of liquids
A
and
B
at
298
K
is
300
m
m
H
g
and
450
m
m
H
g
. Calculate the mole fraction of
A
in the mixture.
[Given total vapour pressure of solution
=
405
m
m
H
g
.]
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Thermochemistry
CHEMISTRY
Watch in App
Explore more
Heat of Reaction
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app