The trajectory of projectile is represented by Y - -3x - gx22- The angle of projection is-

The correct option is C 60^o The equation of trajectory of projectile is y=xtanθ gx^22u^2cos^2θ On comparing coefficient with given #160;trajectory ...

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Standard XII

Physics

Summary for Time, Height and Range

The trajector...

Question

The trajectory of projectile is represented by $Y = \sqrt{3} x - \frac{g x^{2}}{2}$ . The angle of projection is:

30^{o}

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45^{o}

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60^{o}

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none of these

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Solution

The correct option is C $60^{o}$
The equation of trajectory of projectile is $y = x tan θ - \frac{g x^{2}}{2 u^{2} {cos}^{2} θ}$
On comparing coefficient with given trajectory of projectile,we have
$tan θ = \sqrt{3}$
$\Rightarrow θ = 60^{0}$
Therefore, C is correct option.

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The trajectory of projectile is represented by Y=√3x−gx22. The angle of projection is:

The correct option is C 60oThe equation of trajectory of projectile is y=xtanθ−gx22u2cos2θOn comparing coefficient with given trajectory of projectile,we havetanθ=√3⇒θ=600Therefore, C is correct option.

The trajectory of projectile is represented by $Y = \sqrt{3} x - \frac{g x^{2}}{2}$ . The angle of projection is:

The correct option is C $60^{o}$
The equation of trajectory of projectile is $y = x tan θ - \frac{g x^{2}}{2 u^{2} {cos}^{2} θ}$
On comparing coefficient with given trajectory of projectile,we have
$tan θ = \sqrt{3}$
$\Rightarrow θ = 60^{0}$
Therefore, C is correct option.