The translational kinetic energy of 1mole of an ideal gas at standard temperature is close to
A
3403J
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B
3000J
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C
2342J
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D
1564J
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Solution
The correct option is A3403J We know that,
Translational kinetic energy, E=32PV
Using ideal gas equation, PV=nRT
For n=1 PV=RT ∴E=32PV=32RT E=32×8.31×273J ≅3403J