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B
∆ LOM ≅ ∆ QOP (by SAS test )
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C
∆ LOM ≅ ∆ POQ (by ASA test )
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D
∆ LMO ≅ ∆ PQO (by SAS test )
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Solution
The correct option is B ∆ LOM ≅ ∆ QOP (by SAS test ) Consider ∆ LOM and ∆ QOP LO = QO ( Given ∠ LOM = ∠ QOP (Vertically opposite angles) MO = PO ( Given )