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Question

The two adjacent sides of a rectangle are 6a+9b and 8a4b. Find its perimeter.

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Solution

It is given that
Sides of a rectangle are 6a+9b and 8a4b
So length =6a+9b and breadth =8a4b
We know that
Perimeter =2 (length + breadth)
Substituting the values
=2(6a+9b+8a4b)
By further calculation
=2(14a+5b)
So we get
=28a+10b

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