The correct option is
B Wall B
Area of wall A =
1554 sq.m.
Gap between two paintings for wall A =
26 m .
Area of wall B =
1600 sq.m.
Gap between two paintings for wall B =
25 m.
To find the wall which can accomodate more number of paintings, divide
1534 by
26 and
1600 by
25.
On doing the division by standard algorithm method,
So, for wall A, number of paintings will be
=59
And, for wall B, number of paintings will be
=64
You know,
64>59.
Hence, out of the two walls,
wall B will have more number of paintings.