The correct option is
B Wall B
Area of wall A =
1554 sq.m.
Gap between two paintings for wall A =
26 m .
Area of wall B =
1600 sq.m.
Gap between two paintings for wall B =
25 m.
To find the wall which can accomodate more number of paintings, divide
1534 by
26 and
1600 by
25.
On doing the division by standard algorithm method,
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1140162/original_Screenshot_2021-05-22_at_3.16.55_PM.png)
So, for wall A, number of paintings will be
=59
And, for wall B, number of paintings will be
=64
You know,
64>59.
Hence, out of the two walls,
wall B will have more number of paintings.