The two compounds $[C o (S O_{4}) {(N H_{3})}_{5}] B r$ and $[C o (S O_{4}) {(N H_{3})}_{5}] C l$ represent

Linkage is isomerism

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Ionisation isomerism

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ordination isomerism

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No isomerism

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Solution

The correct option is D No isomerism
Even formula of compounds is not same so no isomerism.

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Similar questions

Q. The compounds

[C o (S O_{4}) (N H_{3})_{5}] B r

and

[C o (S O_{4}) (N H_{3})_{5}] C l

represents:

The compounds $[C o (S O_{4}) (N H_{3})_{5}] B r$ and $[C o (S O_{4}) (N H_{3})_{5}] C l$ represent
(a) linkage isomerism
(b) ionisation isomerism
(c) coordination isomerism
(d) no isomarism

Q. Complexes

[C o (S O_{4} {(N H_{3})}_{5})] B r

and

[C o B r {(N H_{3})}_{5}] S O_{4}

can be distinguished by :

Match the correct pairs of isomers with their examples.

A)Ionisation (a) $P t (N H_{3})_{2} C l_{2}] [P t (N H_{3})_{4}]$

$[P t C l_{4}]$

B) Linkage (b) $[C r (N H_{3})_{6}] [C o (C N)_{6}]$ & $[C o (N H_{3})_{6} [C r (C N)_{6}]$

C)Coordination (c) $[C o (N H_{3})_{5} (N O_{2})] C l_{2}$ & $[C o (N H_{3})_{5} (O N O)] C l_{2}$

D)Polymerisation (d) $[C o (S O_{4}) (N H_{3})_{5}] B r$ & $[C o (B r (N H_{3})_{5}] S O_{4}$

Q. Which of the following compounds would exhibit co-ordination isomerism?

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The two compounds [Co(SO4)(NH3)5]Br and [Co(SO4)(NH3)5]Cl represent

The correct option is D No isomerismEven formula of compounds is not same so no isomerism.

The two compounds $[C o (S O_{4}) {(N H_{3})}_{5}] B r$ and $[C o (S O_{4}) {(N H_{3})}_{5}] C l$ represent

The correct option is D No isomerism
Even formula of compounds is not same so no isomerism.