The two ends of a metal rod are maintained at temperatures 100∘C and 110∘C.The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200∘C and 210∘C, the rate of heat flow will be :
4.0 J/s
Rate of heat flow = k.A.ΔTx
Since Δ T is same i.e. 10∘ C, the rate of flow will be same i.e. 4.0 J/s.