Question

the two equal sides of an isosceles triangle are taken as y cm and unequal side is taken as x cm.find it perimeter in terms of x and y ​.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{ABC}\mathrm{be}\mathrm{the}\mathrm{isosceles}∆. \\ \mathrm{Let}\mathrm{AB}=\mathrm{AC}=\mathrm{y}\mathrm{cm}\mathrm{and}\mathrm{BC}=\mathrm{x}\mathrm{cm} \\ \mathrm{Perimeter}\mathrm{of}∆\mathrm{ABC}=\mathrm{AB}+\mathrm{BC}+\mathrm{AC}=\mathrm{y}+\mathrm{x}+\mathrm{y}=\left(2\mathrm{y}+\mathrm{x}\right)\mathrm{cm} \end{gathered}$$