You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Standard Deviation

The two obser...

Question

The two observations $A$ & $B$ are given by $100, 101, . . . . . . . .149$ and $200, 201, . . . . . . ., 249$ with $V_{A}$ and $V_{B}$ are variances of $A$ and $B$ than $V_{A}$ is equal to :

V_{B}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100 V_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 V_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 V_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $V_{B}$
$σ x^{2} = \frac{\sum d^{2}}{h}$ {here deviation are taken from mean}
Since, A and B have consecutive integers therefore both have same standard deviation and hence variation
$V_{A} = V_{B} \sum d^{2} i s s a m e$

Suggest Corrections

Similar questions

Q. Suppose a population

A

has

100

observations

101, 102, . . . ., 200

and another population

B

has

100

observations

151, 152, . . . . ., 250

.
If

V_{A}

and

V_{B}

represent the variances of the two populations, respectively, then

\frac{V_{A}}{V_{B}}

Suppose a population A has 100 observations 101, 102,……200 and another population B has 100 observation 151, 152….., 250. If $V_{A}, V_{B}$ represent the variances of the two populations respectively, then $\frac{V_{A}}{V_{B}}$ is

Q. Suppose a population

A

has 100 observations

101, 102, . . . ., 200

and another population

B

has 100 observations

151, 152, 153, . . . ., 250

. If

V_{A}

and

V_{B}

represent the variances of the two populations respectively, then

\frac{V_{A}}{V_{B}}

A, B and C are voltmeters of resistance R,1.5 R and 3R respectively as shown in the figure.When some potential difference is applied between X and Y, the voltmeter readings are $V_{A}, V_{B}$ and $V_{C}$ respectively.Then :

Join BYJU'S Learning Program

The two observations A & B are given by 100,101,........149 and 200,201,.......,249 with VA and VB are variances of A and B than VA is equal to :

The correct option is A VBσx2=∑d2h{here deviation are taken from mean}Since, A and B have consecutive integers therefore both have same standard deviation and hence variation VA=VB∑d2issame

The two observations $A$ & $B$ are given by $100, 101, . . . . . . . .149$ and $200, 201, . . . . . . ., 249$ with $V_{A}$ and $V_{B}$ are variances of $A$ and $B$ than $V_{A}$ is equal to :

The correct option is A $V_{B}$
$σ x^{2} = \frac{\sum d^{2}}{h}$ {here deviation are taken from mean}
Since, A and B have consecutive integers therefore both have same standard deviation and hence variation
$V_{A} = V_{B} \sum d^{2} i s s a m e$