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Resistance

The two Pt el...

Question

The two Pt electrode fitted in a conductance cell are $1.5$ cm apart while the cross sectional area of each electrode is $0.75 c m^{2}$ . What is the cell constant ?

1.125

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0.5

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2.0 c m^{- 1}

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0.2 c m^{- 1}

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Solution

The correct option is D $2.0 c m^{- 1}$
As we know,
$G^{*} = \frac{l}{a} = \frac{1.5 c m}{0.75 c m^{2}} = 2.0 c m^{- 1}$

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