Question

The two Pt electrode fitted in a conductance cell are $1.5$ cm apart while the cross sectional area of each electrode is $0.75c{m}^2$. What is the cell constant ?

• A. $1.125$ cm
• B. $0.5$ cm
• C. $2.0c{m}^{-1}$
• D. $0.2c{m}^{-1}$

Answer 1

Answer: (C)

$2.0c{m}^{-1}$

As we know,
$G^{\ast }=\frac{l}{a}=\frac{1.5cm}{0.75c{m}^2}=2.0c{m}^{-1}$