The type of hybrid orbitals used by the oxygen atom in $C l_{2} O$ molecule is:

s p^{3}

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s p^{2}

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s p

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None

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Solution

The correct option is A $s p^{3}$
Oxygen is $s p^{3}$ hybridized. It forms $2$ bonds with chlorine and has two lone pair of electrons present. Hence, a total of $4$ hybrid orbitals are required.

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s p

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

s p, s p^{2}, s p^{3}

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

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