Question

The $|\underset{–}{HFH}$ bond angle in the following structure

• A. ${130.5}^0$
• B. ${109}^0{28}^{\prime }$
• C. ${116}^0$
• D. ${103}^0$

Answer 1

The correct option is C

${116}^0$

This is HF in its solid form, it has a bond angle of 116 degrees.