The correct option is
D Joule/coulomb
The explanation for correct answer:-
In the case of option D,
- EMF is produced as the energy is converted from one form to another in a generator or a battery as the device does work on the electric charge being transformed within it.
- The work done on a unit of electric charge gained per unit of electric charge,
- Here, W is work done which has the unit joule (J) and Q is the charge with the unit coulomb.
- So, the SI unit of emf is derived as joules per coulomb.
The explanation for incorrect answer:-
In the case of option A,
- Joule is the SI unit of Work.
- Hence it is incorrect.
In the case of option B,
- Joule-Coulomb does not exist.
- Hence it is incorrect.
In the case of option C,
- Joule can be written as Volt-coulomb.
- So Volt-coulomb is also a unit of Work.
- Hence it is incorrect.
Hence, option D is the correct option.