Question

The unit's digit of the sum $(24{)}^{372}+(24{)}^{373}$ is

• A. 5
• B. 2
• C. 4

Answer 1

Unit's digit of $(24{)}^{372}$ is 6 and unit's digit of $(24{)}^{373}$ is 4.
So, the unit's digit of the sum is 0 (6+4=10)