wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The unit vector along 2i3j+k is

A
2i3j+k14
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2i3j+k5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2i3j+k15
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2i3j+k14
We have 2^i3^j+^k
Let u=2^i3^j+^k
Unit vector is of the form ^u=u|u|
^u=2^i3^j+^k2^i3^j+^k
=2^i3^j+^k22+(3)2+(1)2
=2^i3^j+^k4+9+1
^u=2^i3^j+^k14

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Unit Vectors
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon