Question

The upper and lower fixed points of a faulty mercury thermometer are ${210}^{o}F$ and ${34}^{o}F$ respectively. The correct temperature read by this thermometer is

• A. ${22}^{o}F$
• B. ${80}^{o}F$
• C. ${100}^{o}F$
• D. ${122}^{o}F$

Answer 1

Answer: (D)

${122}^{o}F$

$\frac{F-32}{180}=\frac{F-L}{U-L}$

$\frac{F-32}{180}=\frac{F-34}{210-34}$

$\frac{F-32}{180}=\frac{F-34}{176}$

$\frac{F-32}{45}=\frac{F-34}{44}$

$45F-45\times 34=44F-44\times 32$

$45F-44F=1530-1408$

$F=122℉$