Question

The upper end of a wire (diameter $12\text{mm}$ and length $1\text{m}$) is clamped and its other end is twisted through an angle of ${30}^{\circ }$. The angle of shear is

• A. ${18}^{\circ }$
• B. ${0.18}^{\circ }$
• C. ${36}^{\circ }$
• D. ${0.36}^{\circ }$

Answer 1

The correct option is B ${0.18}^{\circ }$

As we know,
$r\theta =l\varphi$
Here, $r=$ Radius of wire, $l=$ length of wire, $\theta =$ angle of twist, $\varphi =$ angle of shear.
$\Rightarrow \varphi =\frac{r\theta }{l}=\frac{6\text{mm}\times {30}^{\circ }}{1\text{m}}={0.18}^{\circ }$