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Question

The value of (0.2)log514+18+116+....10n is

A
4
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B
14
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C
2
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D
12
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Solution

The correct option is C 4
Let's calculate the sum of infinite series 14+18+116+.......
Let's consider it to be S
The series is a GP with first term (a)=14 and common ratio (r)=12
S=a1r
S=12

To find
(15)log512
By Properties of log, we can write it as
(12)2log515
=(12)2log55
=(12)2
=22=4
Hence, option A is correct.

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