1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The value of (102)×(98) is

A
9,992
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9,994
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9,996
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
9,998
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 9,996Concept Involved––––––––––––––––––––: (a+b)(a−b)=a2−b2 Method–––––––––: Using the FOIL rule. F=First terms, O= Outside terms, I = Inside terms, L= Last terms. (102)×(98)=(100+2)×(100−2) =(100)(100)+(100)(−2)+(2)(100)+(2)(−2) =1002−2(100)+2(100)−22 =1002+2(100)−2(100)−22 =1002−22 =10,000−4 =9,996 This is the required expression obtained using FOIL rule. Also, we can use the identity (a+b)(a−b)=a2−b2. (102)×(98)=(100+2)×(100−2) =(100+2)(100−2) =1002−22 =10,000−4 =9,996

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Application of identity ( x + y )( x - y )
MATHEMATICS
Watch in App
Join BYJU'S Learning Program