Question

The value of ($3^0$ + $4^{-1}$) × $2^2$ is ___

Answer 1

Given, ($3^0$ + $4^{-1}$) × $2^2$

Now, $4^{-1}$ = $\frac{1}{4}$ ($\because a^{-1}=$$\frac{1}{a}$),

and, $3^0$ = 1 ($\because a^0=1,wherea\ne 0$)

So, ($3^0$ + $4^{-1}$) × $2^2$ = (1+$\frac{1}{4})$× $2^2$
= $\frac{5}{4}\times 4$ = 5