The value of 3-2- 6-4 is equal to

The correct option is D 10 (3+2)× (6 4) Now, (3+2)=5 and #160; (6 4)=2 ∴ 5× 2 = 10 So, option D is correct. ...

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The value of $(3 + 2) \times (6 - 4)$ is equal to

7

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2

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4

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10

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[(3 + 2) \times (6 - 4) + 2] \times 4

\frac{2^{\frac{1}{2}} \times 3^{\frac{1}{3}} \times 4^{\frac{1}{4}}}{10^{- \frac{1}{5}} \times 5^{\frac{3}{5}}} \div \frac{4^{- \frac{2}{3}} \times 5^{- \frac{7}{5}}}{4^{- \frac{3}{5}} \times 6^{- \frac{1}{3}}}

\frac{1 + 4.343 + 7.4 + 2.3.49 + 7.343}{16 + 2^{6} . 3^{1} + 2^{5} . 3^{3} + 2^{6} . 3^{3} + 2^{4} . 3^{4}}

\frac{3}{2^{3}} + \frac{4}{2^{4} \cdot 3} + \frac{5}{2^{6} \cdot 3} + \frac{6}{2^{7} \cdot 5} + \dots \infty

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