Question

The value of $4({\sin }^4{30}^0+{\cos }^4{60}^0)-3\left({\cos }^2{45}^0{\sin }^2{90}^0\right)$ is

• A. $0$
• B. $1$
• C. $-1$
• D. $-2$

Answer 1

The correct option is C $-1$

$4({\sin }^4{30}^0+{\cos }^4{60}^0)-3{\sin }^2{90}^0{\cos }^2\left({45}^0\right)$

$=4(\frac{1}{16}+\frac{1}{16})-3\left(1\right)\left(\frac{1}{2}\right)$

$=\frac{8}{16}-\frac{3}{2}$

$=\frac{1}{2}-\frac{3}{2}$

$=-1$
Hence answer is $-1$