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Question

The value of [6 × P + 2 ]is , if it is given that

3 1 P

+ 1 P 3
____

5 0 1


A
20
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B
60
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C
80
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D
50
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Solution

The correct options are
C 80
D 50

For ones digit, 8 + 3 = 1
P = 8 and 1 is carried over.

Verification:

For tens digit, 1(carryover) + 1 + 8 = 10

For hundreds digit, 3 + 1 + 1(carry over) = 5

Therefore value of P is 8.
Value of 6 x P + 2 = 6 x 8 + 2
= 48 + 2 = 50


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