Question

The value of $A$ and $Z$ in the following nuclear reaction is

${}_{12}^{25}\text{Mg}{+}_2^4\text{He}{\to }_1^1\text{H}{+}_Z^A\text{X}$

• A. $A=28,Z=13$
• B. $A=14,Z=2$
• C. $A=36,Z=16$
• D. $A=14,Z=8$

Answer 1

The correct option is A $A=28,Z=13$

From conservation of number of nucleons,

$25+4=A+1\Rightarrow A=28$

$12+2=Z+1\Rightarrow Z=13$