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Question

The value of a ×b 2 is

(a) a 2+ b 2- a ·b 2

(b) a 2 b 2- a ·b 2

(c) a 2+ b 2-2 a ·b

(d) a 2+ b 2-a ·b

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Solution

(b) a 2 b 2- a ·b 2

a. b2+a×b2=a b cos θ2+a b sin θ2=a2 b2 cos2 θ+sin2 θ=a2 b2 1=a2 b2 a×b2=a2 b2 -a. b2Thus, the value of a×b2 is a2 b2 -a. b2.

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