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Byju's Answer
Standard XII
Mathematics
Derivative of One Function w.r.t Another
The value of ...
Question
The value of
a
→
×
b
→
2
is
(a)
a
→
2
+
b
→
2
-
a
→
·
b
→
2
(b)
a
→
2
b
→
2
-
a
→
·
b
→
2
(c)
a
→
2
+
b
→
2
-
2
a
→
·
b
→
(d)
a
→
2
+
b
→
2
-
a
→
·
b
→
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Solution
(b)
a
→
2
b
→
2
-
a
→
·
b
→
2
a
→
.
b
→
2
+
a
→
×
b
→
2
=
a
→
b
→
cos
θ
2
+
a
→
b
→
sin
θ
2
=
a
→
2
b
→
2
cos
2
θ
+
sin
2
θ
=
a
→
2
b
→
2
1
=
a
→
2
b
→
2
∴
a
→
×
b
→
2
=
a
→
2
b
→
2
-
a
→
.
b
→
2
Thus
,
the
value
of
a
→
×
b
→
2
is
a
→
2
b
→
2
-
a
→
.
b
→
2
.
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Similar questions
Q.
Question 32
The value of
(
a
+
b
)
2
+
(
a
−
b
)
2
is
a)
2
a
+
2
b
b)
2
a
−
2
b
c)
2
a
2
+
2
b
2
a)
2
a
2
+
2
b
2
Q.
Question 33
The value of
(
a
+
b
)
2
−
(
a
−
b
)
2
is
a)
4
a
b
b)
−
4
a
b
c)
2
a
2
+
2
b
2
d)
2
a
2
−
2
b
2
Q.
a
→
b
→
a
→
×
b
→
+
a
→
.
b
→
2
=
(a)
a
→
2
b
→
2
(b)
a
→
+
b
→
2
(c)
a
→
2
+
b
→
2
(d)
2
a
→
2
b
→
2
Q.
The value of determinant
∣
∣ ∣ ∣
∣
1
+
a
2
−
b
2
2
a
b
−
2
b
2
a
b
1
−
a
2
+
b
2
2
a
2
b
−
2
a
1
−
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b
2
∣
∣ ∣ ∣
∣
is
Q.
If a
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+ c
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= 2(a + 2b - 2c ) - 9 . Then ,find a + b + c
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