All2 e n d bmatrix - begin bmatrix 1 bmatrix A- 1B- -1C- 2D- -2

The correct option is B 1By matrix multiplication we have nbsp; 2a+a^2+2=1⇒(a+1)^2=0 So a= 1 ...

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Nilpotent Matrix

all2 e n d b...

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The value of $a$ if $[\begin{matrix} 1 & a & 1 \end{matrix}] ⎡ ⎢ ⎣ \begin{matrix} 2 a a 2 \end{matrix} ⎤ ⎥ ⎦ = [\begin{matrix} 1 \end{matrix}]$

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