Approach to Solve Depreciation Rate Based Questions
The value of ...
Question
The value of a property decrease every year at the rate of 5% . if the present value is ₹411540 what was its value 3 years ago
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Solution
Value of property decrease every year = 5% Present value = 411540 Original value= x According to question:- 411540 = x* (100-5)/100 (formula) 411540 = x* 95/100 x = 411540*100/95 (transversal property) x = 433200 (value 1year ago) Now value for 2 year ago:- (putting principle as 433200) 433200 = x*(100-5)/100 (as it is given in question decrease 5%) 433200 = x*95/100 x = 433200*100/95 x = 456000 (value 2 years ago) Now value for 3 years ago (putting principle as 456000) 456000 = x*(100-5)/100 456000 = x*95/100 x = 456000*100/95 x = 480000 ANS.