Question

The value of azimuthal quantum number (l) and magnetic quantum number (m) for the outermost electron in $C{l}^{-}$ ion are:

• A. $1\text{and}+2$
• B. $2\text{and}+1$
• C. $3\text{and}-1$
• D. $1\text{and}-1$

Answer 1

The correct option is D $1\text{and}-1$

The electronic configuration of $C{l}^{-}$ is: $1s^{2}2s^{2}2p^{6}3s^{2}3p^6$
So the outermost electron will lie in $3p$ orbital. Thus the aimuthal quantum number ($l$) will be $1$.
Again, the possible value of magnetic quantum number lies in the range $+l\text{to}-l$. So the correct option is (D).