Question

The value of b if $f\left(x\right)=x^2+4\sqrt{x}+b$ and $f\left(16\right)=275$ is:

• A. 3
• B. 2
• C. 1
• D. 0

Answer 1

The correct option is A

3

Putting the value of x = 16 in $x^2+4\sqrt{x}+b$

${16}^2+16+b=275$

$b=275-272$

$=3$