The value of capacitance of capacitors shown in above diagram are C1 - C2 - C3 - C4 - 8 - C - C5 - 10 - C- The equivalent capacitance between P and Q is-

The correct option is A 8 μ F As the ratio C_1C_3=C_2C_4 , this is simply a wheatstone bridge. So we can neglect the capacitor between R and S. now s ...

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Standard XII

Physics

Charges on Conductors

The value of ...

Question

The value of capacitance of capacitors shown in above diagram are $C_{1} = C_{2} = C_{3} = C_{4} = 8$ $μ$ C $; C_{5} = 10 μ C$ . The equivalent capacitance between P and Q is:

8 μ F

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24 μ F

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16 μ F

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15 μ F

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Solution

The correct option is A $8 μ F$
As the ratio $\frac{C_{1}}{C_{3}} = \frac{C_{2}}{C_{4}}$ , this is simply a wheatstone bridge. So we can neglect the capacitor between R and S. now simplifying the circuit there are four capacitors
Capacitor between P,R and R,Q are in series $C_{1 e q} = \frac{8 \times 8}{8 + 8} = 4 μ F$
same for capacitors between P,S and S,Q, hence $C_{2 e q} = 4 μ F$
now these two capacitors are in parallel
$C_{e q} = 4 + 4 = 8 μ F$

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Similar questions

Q. The capacitors

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Q. Three capacitors

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The effective capacitance between P and Q of the figure below is :

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Q. In the given figure, the capacitors

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The value of capacitance of capacitors shown in above diagram are C1=C2=C3=C4=8μ C ;C5=10μC. The equivalent capacitance between P and Q is:

The value of capacitance of capacitors shown in above diagram are $C_{1} = C_{2} = C_{3} = C_{4} = 8$ $μ$ C $; C_{5} = 10 μ C$ . The equivalent capacitance between P and Q is: