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Question

The value of capacitance of capacitors shown in above diagram are C1=C2=C3=C4=8μ C ;C5=10μC. The equivalent capacitance between P and Q is:

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A
8μF
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B
24μF
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C
16μF
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D
15μF
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Solution

The correct option is A 8μF
As the ratio C1C3=C2C4, this is simply a wheatstone bridge. So we can neglect the capacitor between R and S. now simplifying the circuit there are four capacitors
Capacitor between P,R and R,Q are in series C1eq=8×88+8=4μF
same for capacitors between P,S and S,Q, hence C2eq=4μF
now these two capacitors are in parallel
Ceq=4+4=8μF

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