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Question

The value of cos210o−cos10ocos50o+cos210o is equal to

A
43
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B
13
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C
34
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D
3
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Solution

The correct option is C 34
Given, cos210ocos10ocos50o+cos210o

=12(2cos210o2cos10ocos50o+2cos250o)
=12(1+cos20o(cos60o+cos40o)+1+cos100o)
=12(2+cos20o12cos40o+cos(180o80o))
=12(32+cos20o(cos80o+cos40o))
=12(32+cos20o(2cos60ocos20o))
=12(32+cos20o(2(12)cos20o)
=12(32+cos20ocos20o)
=12(32)
=34


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