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Byju's Answer
Standard XII
Mathematics
Parametric Differentiation
The value of ...
Question
The value of
cos
50
°
cos
130
°
is _____________.
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Solution
cos
50
°
cos
130
°
=
cos
50
°
cos
180
°
-
50
°
=
cos
50
°
-
cos
50
°
∵
cos
180
°
-
θ
=
-
cos
θ
=
-
1
Hence
cos
50
°
cos
130
°
=
-
1
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