wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of cosπ7+cos2π7+cos3π7+cos4π7+cos5π7+cos6π7+cos7π7 is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1
We have,
cosπ7+cos2π7+cos3π7+cos4π7+cos5π7+cos6π7+cos7π7
=(cosπ7+cos6π7)+(cos2π7+cos5π7)+(cos3π7+cos4π7)+cosπ
=(cosπ7+cos(ππ7))+(cos2π7+cos(π2π7))+(cos3π7+cos(π3π7))+(1)
=0+0+01=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Transformations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon