The value of -4- -4- is

Simplify the given expression using trigonometric formula Given Expression: (π4+θ) (π4 θ) (A+B)= A B 1 B+ A nbsp; & (A B)= A B+1 B A ∴(π4+θ) (π4 θ ...

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Standard X

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The value of ...

Question

The value of

$cot (\frac{π}{4} + θ) cot (\frac{π}{4} - θ)$ is

not defined

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Solution

The correct option is C $1$
Simplify the given expression using trigonometric formula

Given Expression:
$cot (\frac{π}{4} + θ) cot (\frac{π}{4} - θ)$

$cot (A + B) = \frac{cot A cot B - 1}{cot B + cot A} &$

$cot (A - B) = \frac{cot A cot B + 1}{cot B - cot A}$

$∴ cot (\frac{π}{4} + θ) cot (\frac{π}{4} - θ)$

$= \frac{cot (\frac{π}{4}) cot θ - 1}{cot θ + cot (\frac{π}{4})} \times \frac{cot (\frac{π}{4}) cot θ + 1}{cot θ - cot (\frac{π}{4})}$

$= \frac{cot θ - 1}{cot θ + 1} \times \frac{cot θ + 1}{cot θ - 1}$

$= 1$

Hence, option $(C)$ is correct.

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The value of cot(π4+θ)cot(π4−θ) is

The value of

$cot (\frac{π}{4} + θ) cot (\frac{π}{4} - θ)$ is