The value of $cos ({sin}^{- 1} 3 / 5)$ is?

+ 3 / 5

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- 3 / 5

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- 4 / 5

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+ 4 / 5

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Solution

The correct option is C $+ 4 / 5$
Given, $cos ({sin}^{- 1} \frac{3}{5}) = cos ⎛ ⎝ {cos}^{- 1} ⎛ ⎝ \sqrt{1 - {(\frac{3}{5})}^{2}} ⎞ ⎠ ⎞ ⎠$
$= cos ({cos}^{- 1} (\frac{4}{5})) = \frac{4}{5}$

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Similar questions

The value of the given expression is ___
$[[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}]$
$+ [{27 \times (- 2)} \div (- 3 - 3)]$
$+ [{(- 3) \times (- 3) \times 5} \div (- 3)]]$

What is the value of the given expression?
$[[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}]$
$+ [{27 \times (- 2)} \div (- 3 - 3)]$
$+ [{(- 3) \times (- 3) \times 5} \div (- 3)]]$

Q. Prove the following:

cos ({sin}^{- 1} \frac{3}{5} + {cot}^{- 1} \frac{3}{2}) = \frac{6}{5 \sqrt{13}} .

Find the value of m and n.
$4 m + 3 n + 24 = 0 7 m - 2 n = - 13$

Q. Let

N = \frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} . \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}

, then the value of

{log}_{2} N =

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The value of cos(sin−13/5) is?

The correct option is C +4/5Given, cos(sin−135)=cos⎛⎝cos−1⎛⎝√1−(35)2⎞⎠⎞⎠=cos(cos−1(45))=45

The value of $cos ({sin}^{- 1} 3 / 5)$ is?

The correct option is C $+ 4 / 5$
Given, $cos ({sin}^{- 1} \frac{3}{5}) = cos ⎛ ⎝ {cos}^{- 1} ⎛ ⎝ \sqrt{1 - {(\frac{3}{5})}^{2}} ⎞ ⎠ ⎞ ⎠$
$= cos ({cos}^{- 1} (\frac{4}{5})) = \frac{4}{5}$