The value of lim x- 0 - x 2 -1 -1 - x 2 -16 -4 is

The correct option is B 4 lim #160; #160;_ x→ 0 √( x^ 2 +1 ) 1 √( x^ 2 +16 ) 4 #160; It is 0 0 form then, by using L ...

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The value of $lim x \to 0 \frac{\sqrt{x^{2} + 1} - 1}{\sqrt{x^{2} + 16} - 4}$ is

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lim x \to 0 \frac{\sqrt{x^{2} + 1} - 1}{\sqrt{x^{2} + 16} - 4}

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$(v i) {lim}_{x \to \frac{π^{-}}{2}} t a n x$

$(v i i) {lim}_{x \to \frac{π}{2^{+}}} s e c x$

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$(i x) {lim}_{x \to - 2^{+}} \frac{x^{2} - 1}{2 x + 4}$

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lim x \to 0 \frac{\sqrt[3]{1 + x^{2}} - \sqrt[4]{1 + 2 x}}{x + x^{2}}

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