The value of lim x- -1 x 2 -3x-2 x 2 -4x-3 is

The correct option is D 1/2 #160;lim _ x→ 1 x ^ 2 +3x+2 x ^ 2 +4x+3 #160; #160;lim _ x→ 1 x ^ 2 +2x+x+2 x ^ 2 +3x+x+3 #160; #16 ...

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The value of $lim x \to - 1 \frac{x^{2} + 3 x + 2}{x^{2} + 4 x + 3}$ is

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\frac{1}{2}

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lim x \to 2 [\frac{1}{x {(x - 2)}^{2}} - \frac{1}{(x^{2} - 3 x + 2)}]

Evaluate the following one sided limits:

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\frac{1}{x^{2} + 3 x + 2} + \frac{1}{x^{2} + 5 x + 6} - \frac{2}{x^{2} + 4 x + 3}

i .

lim x \to 1 [\frac{x^{2} + 1}{x + 100}]

i i .

lim x \to 2 [\frac{x^{3} - 4 x^{2} + 4 x}{x^{2} - 4}]

i i i .

lim x \to 2 [\frac{x^{2} - 4}{x^{3} - 4 x^{2} + 4 x}]

i v .

lim x \to 2 [\frac{x^{3} - 2 x^{2}}{x^{2} - 5 x + 6}]

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lim x \to 1 [\frac{x - 2}{x^{2} - x} - \frac{1}{x^{3} - 3 x^{2} + 2 x}]

Simplify: $\frac{1}{x^{2} - 3 x + 2} + \frac{1}{x^{2} - 5 x + 6} + \frac{1}{x^{2} - 4 x + 3}$

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